HELP!!!!! PLSif alpha and beta are roots of equation x²+6x+k=0 and 3alpha+2beta=-20 then k=????
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Given,
x²-6x+a=0
a,3 are the zeroes of the polynomial
⇒a+3 = 6 - - -(i)
a3 = a - - - - - (ii)
Given
3a+23 = 20 - - -(iii)
Solving (i) and (iii) we get
a = 8
Substituting these values (ii) we get
⇒(8)(-2) = a
⇒a = -16
x²-6x+a=0
a,3 are the zeroes of the polynomial
⇒a+3 = 6 - - -(i)
a3 = a - - - - - (ii)
Given
3a+23 = 20 - - -(iii)
Solving (i) and (iii) we get
a = 8
Substituting these values (ii) we get
⇒(8)(-2) = a
⇒a = -16
POSITIVE:
a,3 are zeroes of polynomial.......?? how...plz clarify a little plzz
The a,3 numbers in the polynomial are zeroes
okay
thks
welcome
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