Question

help.... plzzzzz.. ​

Answer 1

GivEn:-

Length of ladder = 10 m

Base of ladder from the wall = 6 m

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To find:-

How far up the wall does the top of ladder reach?

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Solution:-

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We know that,

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Wall makes an angle of 90°.

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$\underline{\bigstar\:\boldsymbol{Using\: Pythagoras\:Theorem\::}}$

$\setlength{\unitlength}{1.2cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf P}\put(4,2.5){\large\bf 10 m}\put(2.8,.3){\large\bf 6 m}\put(1.02,1.02){\framebox(0.3,0.3)}\end{picture}$

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$\sf Here \begin{cases} & \sf{Hypotenuse,\;H = \bf{10\;cm}} \\ & \sf{Base,\;B = \bf{6\;cm}} \end{cases}$

$\star\;{\boxed{\sf{\purple{(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2}}}}$

$\dag\;{\underline{\frak{Putting\;values\;:}}}$

$:\implies\sf (10)^2 = (6)^2 + (P)^2\\ \\ :\implies\sf 100 = 36 = P^2\\ \\ :\implies\sf P^2 = 100 - 36\\ \\ :\implies\sf P^2 = 64\\ \\ :\implies\sf P = \sqrt{64}\\ \\ :\implies{\boxed{\sf{\pink{P = 8\;cm}}}}\;\bigstar$

$\therefore$ Hence, the top of ladder reach 8 m up on the wall.