Question

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Answer 1

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Answer 2

●HERE IS YOUR ANSWER...


$\frac{log_{3}8 }{ log_{9}16 \: \: \: log_{4}10 } \\ \\ = \frac{ log_{3}(2) {}^{3} }{ log_{(3) {}^{2} }(2) {}^{4} \: .\: log_{(2) {}^{2} }(10) } \\ \\ = \frac{3 log_{3}2 }{ \frac{4}{2} log_{3}2 \: .\: \frac{1}{2} log_{2}10 } \\ \\ = \frac{3 log_{3}2}{2 log_{3}2 \: . \frac{1}{2} log_{2}10} \\ \\ = \frac{3 log_{3}2 }{ log_{ 3}2 \: .\: log_{2}10 } \\ \\ = \frac{3}{ log_{2}10} \\ \\ = 3 \times log_{10}2 \\ \\ = 3 \times 0.30103 \: \: \: \: ( log_{10}2 = 0.30103) \\ \\ = 0.90309$


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