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If (2^n + 1) theta=π, then find the value of..
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Step-by-step explanation:
(2^n +1) theta = π
2^n theta + theta = π
2^n theta = π-theta
subtitute n=0 2^0 theta= π - theta
theta= π - theta
subtitute n=1 2^1 theta = π - theta
2theta= π - theta
so on n=n 2^(n-1) theta = π - theta
2^ncostheta*cos2theta*cos2^2theta.......cos2^n-1theta
=2^n*cos(π - theta) * cos( π - theta).....n times
=2^n(-costheta).....nytimes
=2^n(-costheta)^n
=(-2costheta)^n
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