Question

Help required.







If (2^n + 1) theta=π, then find the value of..





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Answer 1

Step-by-step explanation:

(2^n +1) theta = π

2^n theta + theta = π

2^n theta = π-theta

subtitute n=0 2^0 theta= π - theta

theta= π - theta

subtitute n=1 2^1 theta = π - theta

2theta= π - theta

so on n=n 2^(n-1) theta = π - theta

2^ncostheta*cos2theta*cos2^2theta.......cos2^n-1theta

=2^n*cos(π - theta) * cos( π - theta).....n times

=2^n(-costheta).....nytimes

=2^n(-costheta)^n

=(-2costheta)^n