help to prove this Question
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abhi178 - The Sage
LHS = {cos(π+x).cos(-x)}/{sin(π-x).cos(π/2-x)}
we know,
cos(π+x) = -cosx
sin(π-x) = sinx
cos(-x) = cosx
cos(π/2 + x) = -sinx, use this above .
LHS = {(-cosx).cosx}/{sinx.(-sinx}
= cos²x/sin²x
= cot²x = RHS
Anonymous:
Follow Abhi178... since this answer is his
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