Question

Helppp!!!

1. Evaluate 400 × 15 + 400 × 25 + 400 × 10

2. The sum of two integers is -37, if one of them is 20. find the other

3. find the unknown angles in a triangle ABC is given below (in inserted image)
A is 40°
B is x°
C is y°​

Answer 1

Step-by-step explanation:

1.

400×15+400×25+400×10

= 400×(15+25+10)

= 400×50= 20000

2.

The sum of two integers = -37

One of them = 20

Another one = -37-20 = -57

3.

in a triangle ABC

angle A + angle B + angle C = 180⁰

angle A = 40⁰

AB = BC

=>angle A = Angle C = 40⁰

angle B = 180⁰-(angle A+angle C)

= 180⁰-(40⁰+40⁰)

= 180⁰-80⁰

= 100⁰

Answer 2

Question [1]

- Evaluate 400 × 15 + 400 × 25 + 400 × 10

Solution -

The given expression can we written like this:

$\dashrightarrow$ 400 × 15 + 400 × 25 + 400 ×10

$\dashrightarrow$ 400 × (15 + 25 + 10)

$\dashrightarrow$ 400 × (50)

$\dashrightarrow$ 20000

Hence, The answer is 20000

Question [2]

The sum of two integers is -37, if one of them is 20. find the other

Solution -

In the question, It is given that sum of two integers is -37 and one of them is 20 and we need to find the other one.. Let's find out

Let the other integer be x

Sum of two integers = x + 20

$\:\twoheadrightarrow$ x + 20 = -37

$\:\twoheadrightarrow$ x = — 37 — 20

$\:\twoheadrightarrow$ x = — 57

Let us Clarify: — 57 + 20 = -37

Hence, Solved

Question [3]

Find the unknown angles in a triangle ABC is given below (In inserted image)

A is 40°; B is x°; C is y°

Solution -

In the question, It is concluded that ∆ABC has 3 sides with 2 unknown sides and asked to find those where A measures 40° Let's solve this question too..

$\:\rightarrowtail\sf{\angle A = \angle B = {40}^{\circ}}$ [Angle opposite to equal sides]

$\:\rightarrowtail\sf{\angle A + \angle B + \angle C = {180}^{\circ}}$ [Sum of angle of a Triangle]

$\rightarrowtail\sf{{40}^{\circ} + {40}^{\circ} + \angle C ={180}^{\circ}}$

$\rightarrowtail\sf{{80}^{\circ}+\angle C ={180}^{\circ}}$

$\rightarrowtail\sf{\angle C = {80}^{\circ}-{180}^{\circ}}$

$\rightarrowtail\sf\pink{\angle C = {100}^{\circ}}$

Therefore,

All the angles of ∆ABC are:

∠A = 40°

∠B = 40°

∠C = 100°

∠A + ∠B + ∠C = 180°

40° + 40° + 100° = 180°

80° + 100° = 180°

180° = 180°

${\underline{\bf{\dag}{\sf {\red{ \: Hence, \: verified}}}}}$

⠀

Final Answer -

⠀⠀[1] 20000 is the correct and evaluated answer [2] The solution for Question 2nd is -57 [3] Hence, The required unknown values for ∠B is 40° & ∠C is 100°

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