Question

helppp guys plzplsss​

Answer 1

Answer:

a)1/6

b)1/4

c)1/4

d)1/2

e)1/4

Step-by-step explanation:

Total outcomes are:36

a) Favourable outcomes of getting doublets:(1,1),(2,2),(3,3),(4,4),(5,5) and (6,6)

Favourable outcomes=6

Probability=Favourable outcomes/Total outcomes

Probability of getting doublets =6/36=1/6

B) both even numbers:(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)

Favourable outcomes=9

Probability=Favourable outcomes/Total outcomes

Probability of getting even numbers = 9/36=1/4

C) Both prime numbers:

(2,3),(2,5),(3,2),(3,5),(5,2),(5,3),(2,2),(3,3),(5,5)

Favourable outcomes=9

Probability=Favourable outcomes/Total outcomes

Probability of getting prime numbers = 9/36=1/4

d) one even one odd:(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)

Favourable outcomes=18

Probability=Favourable outcomes/Total outcomes

Probability of getting one even one odd numbers = 18/36=1/2

e) Both odd numbers: (1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)

Favourable outcomes=9

Probability=Favourable outcomes/Total outcomes

Probability of getting Both odd numbers numbers = 9/36=1/4

Hope it helps you.