Question

Helppppppppp meeeee plzz

Answer 1

Answer:

$y = \frac{1}{9} x + 2 \\ y = \frac{x + 18}{9} \\ \\ 9y = x + 18 \\ \\ x = 9y - 18 \\ \\ inverse \: of \: f(x) \: is \: g(x) = 9x - 18$

Step-by-step explanation:

$y = \frac{1}{9} x + 2 \\ y = \frac{x + 18}{9} \\ \\ 9y = x + 18 \\ \\ x = 9y - 18 \\ \\ inverse \: of \: f(x) \: is \: g(x) = 9x - 18$

Answer 2

Answer:

Answer:

\begin{gathered}y = \frac{1}{9} x + 2 \\ y = \frac{x + 18}{9} \\ \\ 9y = x + 18 \\ \\ x = 9y - 18 \\ \\ inverse \: of \: f(x) \: is \: g(x) = 9x - 18\end{gathered}

y=

9

1

x+2

y=

9

x+18

9y=x+18

x=9y−18

inverseoff(x)isg(x)=9x−18

Step-by-step explanation:

\begin{gathered}y = \frac{1}{9} x + 2 \\ y = \frac{x + 18}{9} \\ \\ 9y = x + 18 \\ \\ x = 9y - 18 \\ \\ inverse \: of \: f(x) \: is \: g(x) = 9x - 18\end{gathered}

y=

9

1

x+2

y=

9

x+18

9y=x+18

x=9y−18

inverseoff(x)isg(x)=9x−18