Math, asked by christusjoy1pcrt3y, 1 year ago

helppppppppppppp someone I'll mark brainliest​

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Answered by sabarimadhu630
0

Answer:

Step-by-step explanation:

Don't have to mark it as brainliest

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Answered by Anonymous
1

Answer:

 \frac{6}{ \sqrt{x} }  +  \frac{15}{ \sqrt{y} }  = 5 \\  \frac{21}{ \sqrt{x} } -  \frac{10}{ \sqrt{y} }  = 5 \\  \\ let \:  \frac{1}{ \sqrt{x} }   = a \: and \:  \frac{1}{ \sqrt{y} }  = b \\  \\ now \\ 6a + 15b = 5  -  -  -  - (i)\:  \:  \:  \: \\  21a - 10b = 5 \:  -  -  -  - (ii) \\  \\ multiply \: eq.(i) \: by \: 21 \: and \: eq.(ii) \: by \: 6 \:  \: we \: get \\  \\ 126a + 315b = 105 \\ 126a - 60b = 30 \\  \\ now \: by \: elimination \: we \: have \\  \\ 126a + 315b = 105 \\ 126a - 60b = 30 \:  \:  \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ( \: subtract \: ) \\  -  -  -  -  -  -  -  -  \\ 375b = 75 \\  -  -  -  -  -  -  -  -  \\ b =  \frac{75}{375} =  \frac{1}{5}   \\ putting \: b =  \frac{1}{5}  in \: eq.(i) \: we \: get \\ 126a + 315 \times  \frac{1}{5}  = 105 \\ 126a = 42 \\ a =  \frac{42}{126}  =  \frac{1}{3}  \\  \\  \frac{1}{ \sqrt{x} }  = a \\  \frac{1}{ \sqrt{x} }  =  \frac{1}{3}  \\  \sqrt{x}  = 3 \\ (x = 9) \\  \\  \frac{1}{ \sqrt{y} }  = b \\  \frac{1}{ \sqrt{y} }  =  \frac{1}{5}  \\  \sqrt{y}  = 5 \\ (y = 25)

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