Hemant CH3 and halogen which is given preference while both are attached to the phenyl group
UnknownDude:
Halogen
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If you have two groups on an alkane chain that both take prefixes, they are numbered in the way that gives the lowest possible number for both - with the constraint that one or the other end of the chain is carbon #1.
Example: 5-bromo-1-phenylhexane, not 2-bromo-6-phenylhexane.
If you get the same numbers starting at either end of the chain, then the prefixes are numbered in alphabetical order.
Example: 2-bromo-5-phenylhexane, not 5-bromo-2-phenylhexane.
*This is only for alkanes.* If you have C-C multiple bonds, or suffix groups, they always take the lowest number possible and prefixes are numbered however they have to be.
(plz mark my answer as brainlist)
Example: 5-bromo-1-phenylhexane, not 2-bromo-6-phenylhexane.
If you get the same numbers starting at either end of the chain, then the prefixes are numbered in alphabetical order.
Example: 2-bromo-5-phenylhexane, not 5-bromo-2-phenylhexane.
*This is only for alkanes.* If you have C-C multiple bonds, or suffix groups, they always take the lowest number possible and prefixes are numbered however they have to be.
(plz mark my answer as brainlist)
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