Hence, the total weight of the cyl
CAPLE 3
EXERCISE 7C
olurion
17.
Add the following decimals:
1. 9.6. 14.8. 37 and 5.9
2. 23.7. 106.94. 68.9 and 29.5
3. 72.8. 7.68. 16.23 and 0.7
4. 18.6. 84.75, 8.345 and 9.7
5. 8.236. 16.064. 63.8 and 27.53 6. 28.9, 19.64, 123.697 and 0.354
7. 4.37. 9.638, 17.007 and 6.8
48. 14.5, 0.038. 118.573 and 6.84
9. During three days of a week, a rickshaw puller earns ? 32.60, 2 56.80 and 72 respe
What is his total earning during these days?
10. (A man purchases an almirah for 11025, gives * 172.50 as its cartage and spends?
on its repair. How much does the almirah cost him?)
11. Ramesh covers 36 km 235 m by taxi, 4 km 85 m by rickshaw and 1 km 80 m on foot
is the total distance covered by him?
12. A bag contains 45 kg 80 g of sugar and the mass of the empty bag is 950 g. What is the
of the bag containing this much of sugar?
13. Ramu bought 2 m 70 cm cloth for his shirt and 2 m 60 cm cloth for his pyjamas. Find
total length of cloth bought by him.
14. Radhika bought 2 m 5 cm cloth for her salwar and 3 m 35 cm cloth for her shirt. Fir
total length of cloth bought by her.
Answers
Answer:
(1) 9.6, 14.8, 37 and 5.9
Solution: Converting the given decimals, we get
9.6, 14.8, 37.0, 5.9
Writing these decimals in column form and adding, we get:
9.6
14.8
37.0
+5.9
67.3
Hence, the sum of the given decimals is 67.3
(2) 23.7, 106.94, 68.9 and 29.5
Solution: Converting the given decimals, we get
23.70, 106.94, 68.90, 29.50
Writing these decimals in column form and adding, we get:
(23.70+106.94+68.90+29.50) = 229.04
Hence, the sum of the given decimals is 229.04
(3) 72.8, 7.68, 16.23 and 0.7
Solution: Converting the given decimals, we get
72.80, 7.68, 16.23, 0.70
Writing these decimals in column and adding, we get:
(72.80+7.68+16.23+0.70) = 97.41
Hence, the sum of the given decimals is 97.41
(4) 18.6, 84.75, 8.345 and 9.7
Solution: Converting the given decimals, we get
18.600, 84.750, 8.345, 9.700
Writing these decimals in column and adding, we get:
(18.600 + 84.750 + 8.345 + 9.700) = 121.395
Hence, the sum of the given decimals is 121.395
(5) 8.236, 16.064, 63.8 and 27.53
Solution: Converting the given decimals, we get
8.236, 16.064, 63.800, 27.530
Writing these decimals in column and adding, we get:
(8.236 + 16.064 + 63.800 + 27.530) = 115.63
Hence, the sum of the given decimals is 115.63
(6) 28.9, 19.64, 123.697 and 0.354
Solution: Converting the given decimals, we get
28.900, 19.640, 123.697, 0.354
Writing these decimals in column and adding, we get:
(28.900 + 19.640 + 123.697 + 0.354) = 172.591
Hence, the sum of the given decimals is 172.591
(7) 4.37, 9.638, 17.007 and 6.8
Solution: Converting the given decimals, we get
4.370, 9.638, 17.007, 6.800
Writing these decimals in column and adding, we get:
(4.370 + 9.638 + 17.007 + 6.800) = 37.815
Hence, the sum of the given decimals is 37.815
(8) 14.5, 0.038, 118.573 and 6.84
Solution: Converting the given decimals, we get
14.500, 0.038, 118.573, 6.840
Writing these decimals in column and adding, we get:
(14.500 + 0.038 + 118.573 + 6.840) = 139.951
Hence, the sum of the given decimals is 139.951
(9) During three days of a week, a rickshaw puller earns Rs 32.60, Rs 56.80 and Rs 72 respectively. What is his total earning during these days?
Solution: We have:
1st day 32.60 rupees
2nd day 56.80 rupees
3rd day 72.00 rupees
Total earning in three days (32.60 + 56.80 + 72.00) = 161.4
Hence, the earning money of the rickshaw puller is 161.40 rupees.
(10) A man purchase an almirah for Rs 11025, gives 172.50 as its cartage and spends Rs 64.80 on its repair. How much does the almirah cost him?
Solution: We have:
Cost of almirah 11025.00 rupees
Its cartage 172.50 rupees
Spend for the repair 64.80 rupees
Total spends money are (11025.00 + 172.50 + 64.80) = 11262.3 rupees
Hence, The cost of almirah is 11262.30 rupees.
(11) Ramesh covers 36 km 235 m by taxi, 4 km 85 m by rickshaw and 1 km 80 m on foot. What is the total distance covered by him?
Solution: We have:
Distance covered during the taxi 36.235 km
Distance covered by the rickshaw 4.850 km
Distance covered by the foot 1.800 km
The total distance is (36.235 + 4.850 + 1.800) = 41.328
Hence, the length of his journey = 41.400 km = 41 km 400 m.
(12) A bag contains 45 kg 80 g of sugar and the mass of the empty bag is 950 g. What is the mass of the bag containing this much of sugar?
Solution: Weight of empty bag = 0.950 kg
Weight of the sugar filled in it = 45.800 kg
Total weight = (0.950 + 45.080) = 46.3 kg
Hence, the total weight of the bag filled with sugar = 46.30 kg = 46 kg 30 g.
(13) Ramu bought 2 m 70 cm cloth for his shirt and 2 m 60 cm cloth for his pyjamas. Find the total length of cloth bought by him?
Solution: We have:
The length for cloth of shirt = 2.70 m
The length for cloth of pyjamas = 2.60 m
Total length of cloth = (2.70 + 2.60) = 5.3 m
Hence, the total length of cloth bought by him = 5 m 30 cm.
(14) Radhika bought 2 m 5 cm cloth for her salwar and 3 m 35 cm cloth for her shirt. Find the total length of cloth bought by her.
Solution: We have:
The length for her salwar = 2.05 m
The length for her shirt = 3.35 m
Total length of cloth = (2.05 + 3.35) = 5.4 m =5 m 40 cm.
Hence, the total length of cloth bought by her = 5 m 40 c,