Question

Henry built one garden that is 3 feet wide and 3 feet long. He also built a garden that is 3 feet wide and 6 feet long, and a garden that is 3 feet wide and 9 feet long. How do the areas change

Answer 1

here is your answer...............

Answer 2

Answer:

$Areas \: change \: 9\:ft^{2}\:to \:18\:ft^{2}\:and\:27\:ft^{2}$

Step-by-step explanation:

$case:1\\width\:of\:the \:garden (w)=3\:ft,\\Lenth(l)=3\:ft$

$Area\:of\:the\:Garden=l \times w\\=3\:ft \times 3\:ft\\=9\:ft^{2}--(1)$

$case:2\\width\:of\:the \:garden (w)=3\:ft,\\Lenth(l)=6\:ft$

$Area\:of\:the\:Garden=l \times w\\=3\:ft \times 6\:ft\\=18\:ft^{2}--(2)$

$case:3\\width\:of\:the \:garden (w)=3\:ft,\\Lenth(l)=9\:ft$

$Area\:of\:the\:Garden=l \times w\\=3\:ft \times 9\:ft\\=27\:ft^{2}--(3)$

Therefore,

$Areas \: change \: 9\:ft^{2}\:to \:18\:ft^{2}\:and\:27\:ft^{2}$

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