Question

Henry law constant for the molality of Methane in Benzene at 298 kelvin is 4.27 into 10^5 5 mm Hg. calculate the solubility of Methane in Benzene at 298 K under 760 mm Hg.

please solve it if you know​

Answer 1

ᾰṧ-ṧᾰℓᾰՊ ᾰℓᾰ!кṳՊ!

p = k× C

760mm = 4.25 × 10^ 5 mm × C

C = 760 / 4.25 × 10^5

= 178 × 10^-5

= 1.78 × 10^-3

❤thanks❤

Answer 2

p = k× C

760mm = 4.25 × 10^ 5 mm × C

= 178 × 10^-5

= 1.78 × 10^-3

same as above