Question

Henry's constant of four gases A, B, C and D in
water are 40.3, 1.67, 0.413 and 0.611 bar at
298 K and 1 atm. The gas which has maximum
solubility in water at 298 K and 1 atm is
(1) A
(3) C.
(2) B
(4) D​

Answer 1

Answer:

C answer hoga......................

Answer 2

Answer:

At 298K and 1 atm, the gas has maximum solubility in water will be  the gas C.

Explanation:

According to Henry's law, the amount of dissolved gas in the liquid is proportional to the partial pressure of that gas in the liquid.

                   $P_{A}=K_{H}x_{A}$

where $K_{H}$  is Henry's constant

If we consider $P_{A}$ is constant then  $x_{A}$  ∝  $\frac{1}{K_{H}}$

The amount of gas dissolved is inversely proportional to Henry's constant. Higher the value of Henry's constant, lower will be the solubility of the gas in liquid.

For the given gases A, B, C and D, the C gas has lowest value of Henry's constant. therefore gas C has maximum solubility in water.

Therefore the option (3) is correct.