Question

Henry’s law constant for the molality of methane in benzene at 298 Kis 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.

Answer 1

Hey Dear,

◆ Answer -

Solubility = 1.78×10^-3

● Explaination -

# Given -

KH = 4.27×10^5 mm Hg

P = 760 mm Hg

# Solution -

Solubility of methane gas is calculated by Henry's law.

P = KH.s

s = P / KH

s = 760 / 4.27×10^5

s = 1.78×10^-3

Therefore, solubility of methane in Benzene is 1.78×10^-3.

Hope that was helpful...

Answer 2

Answer:

s = P / KH

s = 760 / 4.27×10^5

s = 1.78×10^-3