Question

hepler,
x2+1/X2 if X+1/X=5​

Answer 1

Answer:

23

Step-by-step explanation:

given

$x + \frac{1}{x} = 5 \\ \\ wkt \: \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ \\ now \\ \\ (x + \frac{1}{x} ) {}^{2} = 25 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2x \frac{1}{x} = 25 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 23$

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Answer 2

Answer:

23

Step-by-step explanation:

given

$\begin{lgathered}x + \frac{1}{x} = 5 \\ \\ wkt \: \: {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ \\ now \\ \\ (x + \frac{1}{x} ) {}^{2} = 25 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2x \frac{1}{x} = 25 \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } = 23\end{lgathered}$