Question

Here anyone from Kadapa in Andhra Pradesh.
My question is

Answer 1

AS GIVEN ABOVE
PS IS BISECTS QPR
THEN ANGLE QPS = ANGLE SPR (BISECTOR DIVIDES ANGLE INTO EQUAL TWO EQUAL PARTS)
AND ALSO IT'S GIVEN PR > PQ
THEN ANGLE Q > ANGLE R
NOW IN TRIANGLE PQS AND PSR
ANGLE Q + ANGLE QPS + ANGLE PSQ = 180 = ANGLE R + ANGLE RPS + ANGLE PSR
AS FROM ABOVE
ANGLE QPS = ANGLE RPS
THEN
ANGLE Q + ANGLE PSQ = ANGLE R + ANGLE PSR
NOW AS ANGLE Q > ANGLE R
THEREFORE
ANGLE PSQ < PSR
(FROM ABOVE'S EQUATION)