Here is a question with answer plzzzzzzzzz don't solve the sum explain how to do???
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It is assumed that tens digit is x and unit digit is y. So for example, 39 is written as 3×10+9. So in the form of x and y it will be 10x+y ---(A)
Now x=3y, so by substitution of value of x in eq(A),
10(3y) +y+y=32
30y+2y=32
32y=32
y=1
x=3y
x=3×1
x=3
So no. is 31.
Now x=3y, so by substitution of value of x in eq(A),
10(3y) +y+y=32
30y+2y=32
32y=32
y=1
x=3y
x=3×1
x=3
So no. is 31.
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