Question

Here is a test to how good your math is
In ∆ABC , A = ( 1 , 2 ) ; B = ( 5 , 5 ) , and <ACB = 90° . If area of ∆ABC is to be 6.5 square units , then the possible number of points for C is ?

Answer 1

Hi ,

In ∆ABC ,

A = ( 1 , 2 ) ;

B = ( 5 , 5 ) ;

<ACB = 90°

here hypotenuse = AB

AB = 5 ( by using distance formula )

Therefore ,

by Pythagorean theorem ,

other two sides which makes 90°

must be 3 and ,4 units .

Now , area of ∆ ABC = ( 1/2 ) × 3 × 4

= 6 square units.

But , according to the problem ,

area of Triangle = 6.5 square cm .

we conclude that the possible number of

points for C = 0

I hope this helps you.

:)