Question

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Answer 1

Answer:

product of zeroes of polynomial is given as coefficient of highest degree

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Answer 2

$Let \: the \: zeroes \: of \: the \: given \: cubic \: polynomial \: be \: \\ \alpha, \beta and \: \gamma . \\ Now \: the \: given \: equation \: is \: 2 {x}^{3} - 5 {x}^{2} - 14 + 8$

$We \: know \: that \: \alpha \beta \gamma = \frac{ - d}{a} \: for \: a \: standard \: cubic \: polynomial \\ i.e. \: a {x}^{3} + b {x}^{2} + cx + d$

$Here \: a =2 \: and \: d = 8 \\ So, \: \alpha \beta \gamma = - \frac{8}{2} = - 4.$

So, the answer is -4.