Question

here is your question ​

Answer 1

⚡⚡Here is your answer⚡⚡

refer to the attachment

⭐Mahir⭐

Answer 2

Explanation:

CH4(g)+2O2→CO2(g)+2H2O(l)

internal energy is equal to the heat of combustion

i.e Ov=ΔE

ΔE=Heat capacity of calorimeter × rise in temperature × molar mass of compound/mass of compound

=17.7×0.5×16/0.16=885

O∨=ΔE=-885kjmol^-

heat of combustion at constant volume is equal to the enthalpy

i.e OP=ΔH

HERE

ΔH=ΔE+ΔnRT................(2)

Δn=1-3=-2,T=300K,R=8.314×10^-3kj k^-1mol6-1

Hence,from the equation(2)ΔH=-885+(-2)×8.314×10^-3×300=-890kjmo^-1

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