Question

Here's A Question....!
..
......
Decode The Following...

NINE
+
FINE
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.......
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State All Calculations..!
No Spams! ​

Answer 1

Hey dear ‼️

===>4 digit + 4digit = 5 digit. fine

nine = wives...

so clearly w=1 as f+n=i+10(it generates a carry over)

now,n+n = e,therefore 2n = e.

e+e=s, so we can write 2n+2n=s 0r 4n=s.

we can see that s is 4 times of n.

possible digit between 0-9 that satisfy this condition are 1,4 and 2,8 for n and e respectively.

but n cannot be one as the value of w is alreay 1 so the only choice we have is 2,8.

therefore n=2 and s=8.

from n=2 we can get e=4

now we can put i as 3,5,6,7,9 but if we put i as 5 or above then while finding the value of " f " from eqn f+n=i+10 in double digits so i has to be 3.

therefore i=3.

now i+i=v, so v=6

so finally we get

w=1

n=2

e=4

s=8

i=3

v=6

===>summation of wives =22.

By @iTzAlia❤️✌️

Answer 2

Hey dear ‼️

===>4 digit + 4digit = 5 digit. fine

nine = wives...

so clearly w=1 as f+n=i+10(it generates a carry over)

now,n+n = e,therefore 2n = e.

e+e=s, so we can write 2n+2n=s 0r 4n=s.

we can see that s is 4 times of n.

possible digit between 0-9 that satisfy this condition are 1,4 and 2,8 for n and e respectively.

but n cannot be one as the value of w is alreay 1 so the only choice we have is 2,8.

therefore n=2 and s=8.

from n=2 we can get e=4

now we can put i as 3,5,6,7,9 but if we put i as 5 or above then while finding the value of " f " from eqn f+n=i+10 in double digits so i has to be 3.

therefore i=3.

now i+i=v, so v=6

so finally we get

w=1

n=2

e=4

s=8

i=3

v=6

===>summation of wives =22.