Question

Here's an interesting question for you.It's urgent.

Answer 1

Hey friend,
Here is the answer you were looking for:
$\frac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

We can write it as :

$= \frac{ {5}^{1} \times {5}^{2(n + 1)} - {5}^{2} \times {5}^{2n} }{ {5}^{1} \times {5}^{2n + 3 } - {5}^{2(n + 1)} } \\ \\ = \frac{ {5}^{ 2n + 2} - {5}^{2 + 2n} }{ {5}^{2n + 3} - {5}^{2n + 2} } \\ \\ = \frac{ {5}^{2n + 2} }{ {5}^{2n + 3} } \\ \\ = {5}^{2n + 2 - (2n + 3)} \\ \\ = {5}^{2n + 2 - 2n - 3} \\ \\ = {5}^{ - 1} \\ \\ = \frac{1}{5}$

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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