Question

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Answer 1

Answer:

I hope that is helpful for you

Answer 2

Step-by-step explanation:

Here, we have a colourful spinner which is equally divided into 6 parts.

Thus, n(S) =6

Out of 6, 3 parts are Yellow, 1 part is Orange, 1 part is Blue and 1 part is Green.

If the spinner is spinned,

Event A: The pointer will land on Yellow.

There is only 1 yellow part.

Hence,

n(A) = 1

P(A) = n(A)/n(S)

= 1/6

Ans. The probability that the pointer will land on yellow is 1/6.

Event B: The pointer will land on White.

There are 0 white parts.

Hence,

n(B) =0

P(B) = n(B)/n(S)

= 0/6

=0

Ans. The probability that the pointer will land on white is 0.

Event C: The pointer will land on Blue.

There is only 1 blue part.

Hence,

n(C) = 1

P(C) = n(C)/n(S)

= 1/6

Ans. The probability that the pointer will land on blue is 1/6.

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