Question

Here's the question...

Solve the solve the quadratic equation for X

x^2-2ax-(4b^2-a^2)=0

Answer 1

X2 -2ax-(4b 2- a 2)=0
x^2 -2ax -[(2b)^2-a^2]=0
x^2-(2b+a)x+(2b-a)x-(2b+a)(2b-a)=0
x[x-(2b+a)]+(2b-a)[x-(2b+a)]=0
[x-(2b+a)][x+(2b-a)]=0
therefore
x-(2b+a)=0 or x+(2b-a)=0
x=2b+a or x= a-2b

If it was helpful mark it brainliest answer.

Answer 2

here is ur answer mate
x ²- 2ax- (4b² -a²)=0
x²-2ax -((2b)²-a²)=0
x²(-2b+a)x+(2b-a)x + (2b+a)( 2b - a)=0
x(x-(2b+a )x +(2b -a) x-2b+a =0
( x-2b+a )(x+2b -a )=0
so
x=2b-a or x=-2b+a
hope it helps
mark brainliest