Here x , 2x+10,5x+2 are in AP ... then find the value of x ?
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Answer:
x , 2x+10 , 5x+2 are in AP
d=d2-d1 , d =d3-d2
2x+10 - x =5x+2 -(2x+10)
x+10 = 3x - 8
3x - x = 10+8
2x =18
x=9
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sairambandari:
tq
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