Question

Herman scored 40 marks in a test, getting 4 marks for each
right answer and losing 1 mark for each wrong answer. If
the number of wrong answers is 1 less than his number of
correct answers, then how many questions did he answer
correctly?​

Answer 1

Step-by-step explanation:

Hope it is of some help.......

Answer 2

Answer:

$\sf\large\underline{Let:-}$

$\sf{\implies The\: number\:_{(correct\:question)}=x}$

$\sf{\implies The\: number\:_{(wrong\:question)}=x}$

$\sf\large\underline{To\:Find:-}$

$\sf{\implies The\: number\:_{(correct\:question)}=?}$

$\sf\large\underline{Solution:-}$

To calculate the number of correct question which is given by Herman at first we have to focus on the given Question after that we have to set up equation then solve the equation by solving we get the number of correct question.

$\sf{\implies Calculation\:for\:1st\:equation:-}$

$\sf{\implies Number\:_{(correct\:Q)}-1=Number\:_{(wrong\:Q)}}$

$\tt{\implies x-1=y}$

$\tt{\implies x-y=1---(i)}$

$\sf{\implies Calculation\:for\:2nd\:equation:-}$

$\sf{\implies mark\:_{(correct\:Q)}-mark\:_{(wrong\:Q)}=Total\:_{(marks)}}$

$\tt{\implies 4x-y=40-----(ii)}$

In eq (i) multiply by 4 then subract from (ii):-]

$\tt{\implies 4x-4y=4}$

$\tt{\implies 4x-y=40}$

By solving we get here:-]

$\tt{\implies -3y=-36}$

$\tt{\implies y=12}$

Putting the value of y=12 in eq (i):-]

$\tt{\implies x-y=1}$

$\tt{\implies x-12=1}$

$\tt{\implies x=1+12}$

$\tt{\implies x=13}$

$\sf\large{Hence,}$

$\sf{\implies The\: number\:_{(correct\:question)}=13}$