Question

heron's formula 52cm,54cm,60cm
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Answer 1

Answer:

hey mate here is your answer .....

Step-by-step explanation:

given: side 1 of triangle = 52 cm ,side 2 =54cm, side3 of triangle =60 cm

to find: area of the triangle by herons formula

so let side 1 =a, side2= b, side3=c

therefore

s=(a+b+c)/2

so. s=(52+54+60)/2

so. s=(166)/2

so. s=83

Now putting half perimeter. i.e- s in herons formula

we get: area=

$\sqrt{83(83 - 52)(83 - 54)(83 - 60)}$

$\sqrt{83(31)(29)(23)}$

$\sqrt{83 \times 31 \times 29 \times 23}$

$\sqrt{1716191}$

=1310.03