Question

find the value of n when 3^-7×3^2n+3=3^11÷3^5

Answer 1

Answer:

n= 5

Step-by-step explanation:

${3}^{ - 7} \times {3}^{2n + 3} = {3}^{11} \div {3}^{5} \\ {3}^{ - 7 + 2n + 3} = {3}^{11 - 5} \\ {3}^{2n - 4} = {3}^{6} \\ \\ since \: base \: is \: same \: \\ then \: power \: should \: be \: equal \\ 2n - 4 = 6 \\ n = 5$

VERIFICATION

${3}^{ - 7} \times {3}^{(2 \times 5) + 3} = {3}^{11} \div {3}^{5} \\ {3}^{ - 7 + 13} = {3}^{6} \\ {3}^{6} = {3}^{6} \\ lhs = rhs$

Answer 2

Answer:

Step-by-step explanation: