Question

Heron's formula is1 pointΔ =√(s(s+a)(s+b)(s+c))Δ = √((s-a)(s-b)(s-c))Δ = √(s(s-a)(s-b)(s-c)) ,S= a+b+cΔ = √(s(s-a)(s-b)(s-c)) , 2S=a+b+c​

Answer 1

$\mathfrak{\bf{\orange{ANSWER}}}$

Heron's Formula:

$\pink{\underline{\boxed{Area = √( s(s-a)(s-b)(s-c) )}}}$

☞ s = (a+b+c)/2

Therefore,

━☞ 2S = a +b+c

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