Hey , A Geometric problem !
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In the right angled triangle ABC , angle A = 90° and AD _|_ BC . Then AD / DC = ?
( Appropriate explanation required ! )
Prajas:
please check the question.it is incorrect.
Answers
Answered by
7
Hii There ...
HERE IS UR ANS...
HOPE IT HELPS:)
MARK AS BRAINLIEST PLZZ!!!
HERE IS UR ANS...
HOPE IT HELPS:)
MARK AS BRAINLIEST PLZZ!!!
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thnks
hey...wait a second
Is anything wrong? @racks? Are you satisfied with this Answer?
yeah !! it is correct
Although...i m not sure...can u figure it out
@anvi
it's correct i guess ;)
okay
Answered by
7
Hi ,
Draw a rough diagram ,
Given :
In triangle ABC , <A = 90° and
AD is perpendicular to BC
proof :
In Triangle BAC , AD Perpendicular to BC
∆ ADB ~ ∆ BAC and
∆ ADC ~ ∆ BCA
Therefore , ∆ ADB ~ ∆ CDA
so , AD/ DC = AB/CA
= BD/AD
Therefore
BD/AD = AB/AC
or
AD/DC = DB/AD
AD² = BD × CD
I hope this helps you.
:)
Draw a rough diagram ,
Given :
In triangle ABC , <A = 90° and
AD is perpendicular to BC
proof :
In Triangle BAC , AD Perpendicular to BC
∆ ADB ~ ∆ BAC and
∆ ADC ~ ∆ BCA
Therefore , ∆ ADB ~ ∆ CDA
so , AD/ DC = AB/CA
= BD/AD
Therefore
BD/AD = AB/AC
or
AD/DC = DB/AD
AD² = BD × CD
I hope this helps you.
:)
sir...what will be the answer..if the question is like..... Find BD / AC ?
sorry
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