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Answer 1

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Solution (1)

Let, the total number of deers be x

then,

• no. of deers gone to forest = x / 4
• no. of deers grazing in the field = x / 3
• remaining no. of deers drinking water on the bank of river given = 15

so,

➥ x = (x/4) + (x/3) + 15

taking LCM in RHS

➥ x = (3x + 4x + 12(15)) / (12)

cross multiplting

➥ 12 x = 7 x + 180

➥ 5 x = 180

➥ x = 36

therefore,

• total number of deers is 36.

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Solution (2)

Let, CP of radio be x

then, given that

• SP of radio = 903
• gain% = 5 %

so,

➥ SP = CP + {(gain percent)/100} CP

➥ 903 = CP + ( 5 / 100 ) CP

➥ 903 = CP ( 1 + (5/100) )

➥ 903 = CP ( (100+5) / (100) )

➥ 903 = 105 CP / 100

➥ 105 CP = 90300

➥ CP = 860

therefore,

• Cost price of radio is 860 .

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Solution (3)

Let, Shekar has a total of x sweets

then,

• sweets given to Renu = x / 4
• sweets given to Raji = 5
• sweets left with him after sharing = 7

so,

➥ x = (x/4) + 5 + 7

➥ x - (x/4) = 12

➥ (4x - x) / (4) = 12

➥ 3 x / 4 = 12

➥ 3 x = 48

➥ x = 16

therefore,

• Shekhar did have 16 sweets to start with.

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Answer 2

➡ SOLUTION (1).

⭐ Let the total no of deer's taken be x.

⚫Then,

✏ No.of deer's gone to forest = x/4

✏ No.of deer's grazing in the field = x/3

✏ Remaining no of deer's was drinking water on the bank of river is given = 15

⭐ ATQ:-

=> x = (x/4)+(x/3)+15

⚫Taking L.C.M in the R.H.S

=> x = (3x+4x+12(5))/(12)

⚫ Then with the help of cross multipliting

=> 12x = 7x + 180

=> 12x - 7x = 180

=> 5x = 180

=> x = 180/5

=> x = 36

✔ Total no.of deer's is 36

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➡ SOLUTION (2).

⭐ Let, CP of radio be x

⚫ Given:-

✏ SP of radio is 903

✏ Gain% = 5%

⚫ ATQ:-

=> SP = CP + {(gain%)/100}CP

=> 903 = CP+(5/100) CP

=> 903 = CP (1+(5/100))

=> 903 = CP ((100+5)/(100))

=> 903 = 105 CP/100

=> 105 CP = 90200

=> CP = 90200/105

=> CP= 860

✔ CP of radio is 860.

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➡ SOLUTION (3).

⭐ Let, Shekar has a total of x sweet.

⚫ Then,

✏ Sweet given by Renu = x/4

✏ Sweet given by Raji = 5

✏ Sweet are left with him after sharing = 7

⚫ ATQ:-

=> x = (x+4)+5+7

=> x - (x+4) = 12

=> (4x-x)/(4) = 12

=> 3x/4 = 12

=> 3x = 12×4

=> 3x = 48

=> x = 48/3

=> x = 16

✔ Shekar did have got 16 sweet to start with.

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Step-by-step explanation:

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