Question

Hey answer it plzz .. Only answer is required ✌​

Answer 1

Question :

Four point charges each which charge +q are placed at the four corners of a square of edge length L and a charge $\frac{-q}{4}$ is it centre of the square. The force on the charge at the centre due to other charges is:

Theory :

Coulombs law :

It States that two point charges at rest separated by distance r exert a force on on each other ,which is directly proportional to the product of the magnitude of charges,and inversely proportional to square of the distance between them.

${\purple{\boxed{\large{\bold{F =\dfrac{kq_{1}q_{2} }{r {}^{2} }}}}}}$

Solution :

Here $F_{51}=F_{53}=F_{52}=F_{<54}=F$

$\bf F = \bf \dfrac{k \times q \times \frac{ q}{4} }{( \dfrac{l}{ \sqrt{2} }) {}^{2} }$

$\implies \bf F= \bf \dfrac{kq {}^{2} }{2l {}^{2} }$

Clearly from the diagram $F_{51}\:and\:F_{53}$ cancel each other and $F_{54}\:and\:F_{52}$ cancel each other.

Therefore,The force on the charge at the centre due to other charges is Zero .