Physics, asked by Anonymous, 1 year ago

Hey brainliest answer this if u can........
A child’s toy consists of three cars that are pulled in tandem on small frictionless rollers as shown in below figure. The cars have masses m1 = 3.1 kg, m2 = 2.4 kg, and m3 = 1.2 kg. If they are pulled to the right with a horizontal force P = 6.5 N, find (a) the acceleration of the system, (b) the force exerted by the second car on the third car, and (c) the force exerted by the first car on the second car.

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Answers

Answered by dm7
1
since they lie on a frictionless track and since all 3 blocks are connected by a string the acceleration in each of them will be same

so F=Ma
6.5= 6.7×a
6.5/6.7=65/67=0.97m/s^2

Force exerted by the second car on third will occur due to string
so In F.B.D of 2
Let T1 be force exerted by car 1 on car 2
T2 be force exerted by car 3 on car 2
T1 - T2 = 2.4×0.97=2.33N

similarly T2 = 1.2xa=1.2×0.97=1.16
therefore
force exerted by second car on third car will be
T2 = 1.16 N
and that by First on second will be T1
so
2.33+1.16= 3.49 N


Answer
1)0.97m/s^2
2)1.16N
3)3.49N


Anonymous: Cbse
dm7: no need to worry if you take science your 11th and 12 th will be all this
Anonymous: I am looking forward to take science in plus 1 already
dm7: No need to practice these type of sums in 9th. Enjoy your school life!!!!!!!!!!
Anonymous: Bhaiya I am preparing for Competitive exams right now like ntse. They are all filled up with these type of questions
Anonymous: I love physics as well
dm7: Ok if you are preparing for NTSE then its fine
dm7: actually would like to say one thing, whatever you are learning in 9th and 10th are incomplete or not upto mark when you come in 11th it will all change so abruptly
Anonymous: I know that
Anonymous: But anyway thank you for guiding me
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