N is a four digit perfect square whose decimal digits are each less than 7. If each digit in N is increased by 3, then the new number is also a perfect square. What is the square root of N?
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According to question
Let the digit of the number x
Then
first digit = 7
second digit = 7 + x
and third digit = x
Thus
7 + 7 + x + x = 18
2x = 6
thus x = 3
Let the digit of the number x
Then
first digit = 7
second digit = 7 + x
and third digit = x
Thus
7 + 7 + x + x = 18
2x = 6
thus x = 3
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