Math, asked by Anshika788, 1 year ago

Hey buddy ...........
# give me answer of question no. 16 #
Its urgent .....

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Answered by Anonymous
2
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Answered by roy163
0

Fi=17+F1 +32 +F2 +19 =68+f1+f2

xi=10+ 20+ 20+ 20+ 20=90

fixi=170+ 20f1+ 52+ 20f2+ 39

68+f1+f2=120

f1+f 2=120-68=52-----(1)

X=170+20f1+52+20f2+39/68+f1+f2

50=same utar zaiga

by cross multiplication

f1-f2=4

by eliminating method

f1+f2=52

f1-f2=4

now cancelling f2.

2f1=56

f1=28

putting in equation 1.

f1+f2=52

28+f2=52

f2=24

thus, f1=28 and f2=24

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