Question

hey, can anyone help me with this question please if you answer this then I will mark that guy branliest. This question is of the chapter The number system.

Answer 1

Answer:

$91 \tiny \: 300 \\ i \: hope \: it \: work : )$

Answer 2

Answer:

a = 6 and b = -1/2

Step-by-step explanation:

$\implies\:\dfrac{ ({81}^{1/3} ) \times ( {27}^{1/2} )}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ ({3}^{4 \times 1/3} ) \times ( {3}^{3 \times 1/2} )}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ ({3}^{4/3} ) \times ( {3}^{3/2} )}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ ({3}^{4/3 + 3/2})}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ {3}^{(8 + 9)/6}}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ {3}^{17/6}}{2 \times ( {3}^{5/6} )} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ 22.48}{2 \times 2.5} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ 22.48}{5} + \dfrac{1}{3 + \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ 22.48}{5} + \dfrac{1}{3 + \sqrt{7} } \times \dfrac{3 - \sqrt{7} }{3 - \sqrt{7} } = a + b \sqrt{7}$

$\implies\:\dfrac{ 22.48}{5} + \dfrac{3 - \sqrt{7} }{9 - 7 } = a + b \sqrt{7}$

$\implies\:4.5 + \dfrac{3 - \sqrt{7} }{2} = a + b \sqrt{7}$

$\implies\:\dfrac{9 + 3 - \sqrt{7} }{2} = a + b \sqrt{7}$

$\implies\:\dfrac{12 - \sqrt{7} }{2} = a + b \sqrt{7}$

$\implies\:\dfrac{12}{2} - \dfrac{\sqrt{7} }{2} = a + b \sqrt{7}$

$\implies\:6 - \dfrac{\sqrt{7} }{2} = a + b \sqrt{7}$

Om comparing we get,

a = 6 and b√7 or b = -1/2