CBSE BOARD X, asked by rahila97, 11 months ago

hey can anyone say me basic points on co ordinate geometry........​

Answers

Answered by avni841276
0

Explanation:

The Distance Between two Points.

The Midpoint of a Line Joining Two Points.

The Gradient of a Line Joining Two Points.

Parallel and Perpendicular Lines.

The Equation of a Line Using One Point and the Gradient.

Answered by sarimkhan112005
1

Explanation:

hey there

here are some basic points on co ordinate geometry

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The Distance Between two Points

Draw a line between the two points. Complete a right angle triangle and use Pythagoras' theorem to work out the length of the line.

Between points A and B:

AB2 = (Bx – Ax)2 + (By – Ay)2

The Midpoint of a Line Joining Two Points

The midpoint of the line joining the points (x1, y1) and (x2, y2) is:

[½(x1 + x2), ½(y1 + y2)]

Example

Find the coordinates of the midpoint of the line joining (1, 2) and (3, 1).

Midpoint = [½(3 + 1), ½(2 + 1)] = (2, 1.5)

 

The Gradient of a Line Joining Two Points

The gradient of a line joining points (x1, y1) and (x2, y2) is (y2 - y1)/(x2 - x1).

 

Parallel and Perpendicular Lines

If two lines are parallel, then they have the same gradient.

If two lines are perpendicular, then the product of the gradients of the two lines is -1.

Example

a) y = 2x + 1

b) y = -½ x + 2

c) ½y = x - 3

The gradients of the lines are 2, -½ and 2 respectively. Therefore (a) and (b) and perpendicular, (b) and (c) are perpendicular and (a) and (c) are parallel.

 

The Equation of a Line Using One Point and the Gradient

The equation of a line which has gradient m and which passes through the point (x1, y1) is:

y - y1 = m(x - x1)

Example

Find the equation of the line with gradient 2 passing through (1, 4).

y - 4 = 2(x - 1)

y - 4 = 2x - 2

y = 2x + 2

Since m = y2 - y1

             x2 - x1

The equation of a line passing through (x1, y1) and (x2, y2) can be written as:

y - y1 = y2 - y1

x - x1    x2 - x1

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