what are the two last digit of 3^83
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Step-by-step explanation:
Method #1:#1:
Now,
345=3⋅344=3(32)22=3(10−1)22=3(1−10)22
345=3⋅344=3(32)22=3(10−1)22=3(1−10)22
Now,
(1−10)22≡1−10⋅22(mod100)≡−19≡81
(1−10)22≡1−10⋅22(mod100)≡−19≡81
Method #2:#2:
As (3,10)=1
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