Question

hey dear friends plzz answer this question ....explain also..
❤☺❤☺❤☺❤
The force required to just move up a body to the inclined plane is double the force required to just prevent the body from sliding down the plane.The cofficient of friction is mU..The inclination Theta of the plane is ?????......❤☺❤

Answer 1

Heya

$\theta = {tan}^{ - 1} (3 \mu)$

( Why ? ) Let's do something ->

Case 1 : Move up the body ->

() Forces acting :
(i) Applied Force 'F' up the incline
(ii) Friction down the incline
(iii) mg Vertically downwards
(iv) Normal perpendicular to incline

Write appropriate equations to get :
-> F = mg( sin θ + u cos θ )

Case 2 : Prevent the body from going down ->

() Forces acting :
(i) Applied Force 'F' up the incline
(ii) Friction up the incline
(iii) mg Vertically downwards
(iv) Normal perpendicular to incline

Write appropriate equations to get :
-> F' = mg( sin θ - u cos θ )

Given, F = 2F' and so... You get :

-> ( sin θ + u cos θ ) = 2( sin θ - u cos θ )

=> tan θ = 3u

# And you get the desired Answer

Answer 2

Hi !!!!

Answer is
${ \tan}^{ - 1} \: 3u$
For solution refer to the images attached.

Left one is Image 1 and Right one is Image 2

Hope it helps!!!