Hey dears !!!!
Q.1) How many two digit numbers are divisible by 4 ?
Q.2) How many three digit numbers are divisible by 4 ?
✡✡ Full explanation Answers needed ✡✡✡
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TheIncorporealKlaus:
Why not deletin' this mfn question too, nizzle!
Answers
Answered by
10
(1)
The first two digit number divisible by 4 = 12.
The last two digit number divisible by 4 = 96.
Let a be the first term and d be the common difference.
First term a = 12.
Last term an = 96
We know that an = a + (n - 1) * d
96 = 12 + (n - 1) * 4
84 = 4n - 4
88 = 4n
n = 22.
Therefore there are 22 two-digit numbers divisible by 4.
(2)
The first 3-digit number divisible by 4 = 100
The last three digit number divisible by 4 = 996.
Let a be the first term and d be the common difference.
First term a = 100
Common difference d = 4
Last term an = 996
We know that an = a + (n - 1) * d
996 = 100 + (n - 1) * 4
896 = 4n - 4
900 = 4n
n = 900/4
n = 225.
Therefore there are 225 three digit numbers divisible by 4.
Hope this helps!
The first two digit number divisible by 4 = 12.
The last two digit number divisible by 4 = 96.
Let a be the first term and d be the common difference.
First term a = 12.
Last term an = 96
We know that an = a + (n - 1) * d
96 = 12 + (n - 1) * 4
84 = 4n - 4
88 = 4n
n = 22.
Therefore there are 22 two-digit numbers divisible by 4.
(2)
The first 3-digit number divisible by 4 = 100
The last three digit number divisible by 4 = 996.
Let a be the first term and d be the common difference.
First term a = 100
Common difference d = 4
Last term an = 996
We know that an = a + (n - 1) * d
996 = 100 + (n - 1) * 4
896 = 4n - 4
900 = 4n
n = 900/4
n = 225.
Therefore there are 225 three digit numbers divisible by 4.
Hope this helps!
Answered by
9
hey dear
here is your answer
Solution
Explanation
2 digit numbers are between 10 to 99
first two digit number is divisible by 4 is 12
Last two digit number divisible by 4 is 96
sequence is 12 , 16 ,20 ......... 96
n is the number of term in the above Ap
a = 12
n = 96
d = 4
so
< n = a + ( n - 1 ) d >
Tn = 12 + ( n - 1 ) * 96
4 ( n -1 ) = 96 -12
4 ( n -1) = 84
n -1 = 84 /4
n - 1 = 21
so n = 21 +1
n = 22
hence your answer is 22
Next solution of question
The three digit natural number that are divisible by 4 are
100 , 104 , 108........... 996
it is an Ap where
a = t 1 = 100
d = 4
Let n take = 996
we know that for an ap
< n = a + (n - 1 ) * d >
996 = 100 + ( n - 1 ) *4
996 = 100 + 4n - 4
996 = 96 + 4n
996 -96 = 4n
900 = 4n
900 / 4 = n
so n = 225
hence your next answer is 225
hope it helps
thank you
here is your answer
Solution
Explanation
2 digit numbers are between 10 to 99
first two digit number is divisible by 4 is 12
Last two digit number divisible by 4 is 96
sequence is 12 , 16 ,20 ......... 96
n is the number of term in the above Ap
a = 12
n = 96
d = 4
so
< n = a + ( n - 1 ) d >
Tn = 12 + ( n - 1 ) * 96
4 ( n -1 ) = 96 -12
4 ( n -1) = 84
n -1 = 84 /4
n - 1 = 21
so n = 21 +1
n = 22
hence your answer is 22
Next solution of question
The three digit natural number that are divisible by 4 are
100 , 104 , 108........... 996
it is an Ap where
a = t 1 = 100
d = 4
Let n take = 996
we know that for an ap
< n = a + (n - 1 ) * d >
996 = 100 + ( n - 1 ) *4
996 = 100 + 4n - 4
996 = 96 + 4n
996 -96 = 4n
900 = 4n
900 / 4 = n
so n = 225
hence your next answer is 225
hope it helps
thank you
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