Question

Hey❤️❤️


Focus on study ⚠️
_______________


A card is randomly selected from a standard deck of cards and a die is rolled. What is the probability an even-numbered card is selected and an odd number is rolled?


By Choudhary21 ❤️​

Answer 1

Answer:

P ( die ) = 3/6 = 1/3

Step-by-step explanation:

odd numbers are 1,3 and 5 .

Answer 2

Answer:

$\huge{\underline{\mathtt{\red {Q}\pink{U}\green{E}\blue{S}\purple {T}\orange{I}\red {O}\pink {N}}}}$

A card is randomly selected from a standard deck of cards and a die is rolled. What is the probability an even-numbered card is selected and an odd number is rolled?

$\huge{\underline{\mathtt{\red {A}\pink{N}\green{S}\blue{W}\purple {E}\orange{R}}}}$

1. A = an ace B = a jack

P(ace) = 4/52 = 1/13

P(jack) = 4/52 = 1/13

P(ace and jack) = 0/52 = 0 as there is no card that is both an ace and a jack

P(ace or jack) = P(ace) + P(jack) – P(ace and jack)

= 1/13 + 1/13 - 0

= 2/13

Answer: 2/13

3. A = an ace B = a diamond

P(ace) = 4/52

P(diamond) = 13/52

P(ace and diamond) = 1/52 (this is counting the ace of diamonds)

P(ace or diamond) = P(ace) + P(diamond) – P(ace and diamond)

= 4/52 + 13/52 - 1/52

Answer: 16/52 = 4/13

${\huge{\bold{\overbrace{\mathcal{\red{Hope\ it\ Helps}}}}}}$

${\huge{\bold{\underbrace{\mathcal{\orange{Radhey\ Radhey}}}}}}$