Question

hey friend
pls help me with my questions

Answer 1

1)) no of image =360/given angle - 1

a)) no of image =360/90-1 = 4-1=3

b)) no of images =360/60-1 = 6-1=5

2)) i )) in case of asymmetrical
no of image = 360/50 = appox 7 so Ans:-7

ii )) in case of symmetrical
no of image = 360/50-1 = 7.2-1 = 6.2 approx 6 , so Ans:-6

Answer 2

==================================
⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐
==================================

*⃣ BOOK :- CONCISE ICSE PHYSICS

*⃣ EXERCISE :- 7 (B)

*⃣ CHAPTER :- REFLECTION OF LIGHT

*⃣NUMERICALS

==================================

1] (i) Here, theta = 90°

Therefore, number of images (n)

= (360/90)-1

= 4-1

= 3 (Ans.)

==================================

(ii) Here theta = 60°

Therefore, number of images (n)

= (360/60)-1

= 6-1

= 5 (Ans.)

==================================

2] Given, theta = 50°.

n = 360/50 = 7.2 or 7 (accuracy).

(i) No. Of images formed when the object is placed asymmetrically,
n = 7 (Ans.)

(ii) No. Of images formed when the object is placed symmetrically = n-1 = 7-1 = 6 (Ans.)

==================================

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

==================================