Question

The pressure exerted by 6.0 g of methane gas in a 0.03 m3 vessel at 129 degree Celsius

Answer 1

we know pv= nR T
p= nRT / v
(n= m/M where M is molecular mass
=6/16
=.375)
T is ( 129+273)=402k
R is universal gas constant which is 8.314

put all the things in the equation and you will get p= 4.177885×10^4 pa
thanks ☺

Answer 2

use the ideal gas equation

PV=nRT

where, n= no. of moles

P= pressure

V= volume of the gas

R= universal gas constant

T= temperature in kelvin