Question

Hey friends ❤
A bag contains one rupee 50 paisa and 25 paisa coins in the ratio 5:6:8 amounting to rs.210 . Find the no.of coins of each type . Help me coz tomorrow is my EXAM...
I will mark u brainliest​

Answer 1

Answer:

105, 126, 672

Step-by-step explanation:

Given, Ratio of values = 5 : 6 : 8

                                     = 5 : (6/2) : (8/4)

                                     = 5 : 3 : 2

Given,Total = 210.

Divide 210 in the ratio of 5 : 3 : 2.

(i)

1st part = (210 * 5/10)

            = 105

2nd part = (210 * 3/10)

              = 63.

3rd part = (210 * 8/10)

             = 168

Therefore,

Number of 1-rupee coins = 105.

Number of 50-paise coins = 63 * 2 = 126.

Number of 25-paise coins = 168 * 4 = 672.

Hope it helps!

Answer 2

Here we are given,

Ratio of coins are 5:6:8.

The bag has 1rupees,50 paisa and 25 paisa coins in the given respective ratio.

Now , according to the question=>

let the no. if coins in the bag be 5x,6x and 8x respectively.

Now,

Amount of 1 rupees coins in the bag =(5x)×1 = Rs5x

Amount of 50 paise coins in the bag

= (50x) × 6 = 300x paise = Rs 3x

(Since 1 rupees is 100 paise)

Amount of 25 paise coins in the bag

=(25x) × 8 = 200x paise = Rs 2x

(Since 1 rupees is 100 paise)

Now we have=>

2x + 3x + 5x = 210

=>10x = 210

=>x = 21.

Hence there are=>

Rs 1 coins = 5×21 = 105 coins

50 paise coins = 6×21 = 126 coins

25 paise coins = 8×21 =168 coins.

Also there are a total of 699 coins.