Question

Hey friends !!!

Chemistry problem .

Please solve my problem which is refer to the attachment

Answer 1

A.

Let the number of moles of air pesent in the vessel = n

3/5 th of the original moles of gas has been expelled.

Therefore, the remaining number of moles of air in the vessel = (n – 3/5 n)

   =  2/5 n

At constant pressure and volume,

n1T1= n2T2

n x 300 = 2/5 n x T2

T2 = 750 K

 







B.


On heating vessel to 900 K , let n1 moles be left again n1T1 = n2T2

n1 × 900 = 300 × n

n1 = n/3

moles escaped out = n − n/3 = 2n/3 moles










C .

Let n/2 moles are escaped out at temperature T then

n1T1 = n2T2

= n × 300

T = 600 K

Answer 2

heya mate


The answer of ur question is in pic