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Chemistry problem .
Please solve my problem which is refer to the attachment
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A.
Let the number of moles of air pesent in the vessel = n
3/5 th of the original moles of gas has been expelled.
Therefore, the remaining number of moles of air in the vessel = (n – 3/5 n)
= 2/5 n
At constant pressure and volume,
n1T1= n2T2
n x 300 = 2/5 n x T2
T2 = 750 K
B.
On heating vessel to 900 K , let n1 moles be left again n1T1 = n2T2
n1 × 900 = 300 × n
n1 = n/3
moles escaped out = n − n/3 = 2n/3 moles
C .
Let n/2 moles are escaped out at temperature T then
n1T1 = n2T2
= n × 300
T = 600 K
Let the number of moles of air pesent in the vessel = n
3/5 th of the original moles of gas has been expelled.
Therefore, the remaining number of moles of air in the vessel = (n – 3/5 n)
= 2/5 n
At constant pressure and volume,
n1T1= n2T2
n x 300 = 2/5 n x T2
T2 = 750 K
B.
On heating vessel to 900 K , let n1 moles be left again n1T1 = n2T2
n1 × 900 = 300 × n
n1 = n/3
moles escaped out = n − n/3 = 2n/3 moles
C .
Let n/2 moles are escaped out at temperature T then
n1T1 = n2T2
= n × 300
T = 600 K
Answered by
8
heya mate
The answer of ur question is in pic
The answer of ur question is in pic
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