#
Hey friends

Find the sum of first 'n' even natural numbers. Hence find the sum of the first 20 even natural numbers.

please solve this with proper steps

The answer is n(n+1) and 420

## Answers

Answered by

22

Answer :

The even Natural numbers are as follows -

2, 4, 6, 8, ...

So, the nth term be

= 2 + (n - 1)(2)

= 2 + 2n - 2

= 2n

So, the sum of first n even Natural numbers be

Sn

= n/2 (1st term + nth term)

= n/2 (2 + 2n)

= n (1 + n)

= n (n + 1) [Answer]

Hence, the sum of first 20 even Natural numbers be

S20

= 20 (20 + 1)

= 20 × 21

= 420 [Answer]

How to find nth term?

If a be the first term of an AP and d be the common difference, then the nth term be

tn = a + (n - 1)(d)

#MarkAsBrainliest

The even Natural numbers are as follows -

2, 4, 6, 8, ...

So, the nth term be

= 2 + (n - 1)(2)

= 2 + 2n - 2

= 2n

So, the sum of first n even Natural numbers be

Sn

= n/2 (1st term + nth term)

= n/2 (2 + 2n)

= n (1 + n)

= n (n + 1) [Answer]

Hence, the sum of first 20 even Natural numbers be

S20

= 20 (20 + 1)

= 20 × 21

= 420 [Answer]

How to find nth term?

If a be the first term of an AP and d be the common difference, then the nth term be

tn = a + (n - 1)(d)

#MarkAsBrainliest

Mia123456:
Hey i have a doubt in this step. n/2(2+2n)=n(1+n)? how? can you explain this step to me.thanks

Answered by

2

**Answer:**

l don't know you will say

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