Question

hey friends !!!


here is the question

answer any one.

Answer 1

Hey there !!

▶ Solve by substitution method :-)

2x + 3y = 1.

2x - 4y = -24.

▶ Solution :-)

Given equation :-

=> 2x + 3y = 1.

=> 3y = 1 - 2x.

=> y = $\frac{1 - 2x}{3}$ ........(1).

And, 2x - 4y = -24.........(2).

=> 2x - 4 $( \frac{1 - 2x}{3} )$ = -24.

=> 2x - $( \frac{4 - 8x}{3} )$ = -24.

=> $\frac{6x - 4 + 8x}{3}$ = -24.

=> 14x - 4 = -72.

=> 14x = -72 + 4.

=> 14x = -68.

=> x = $\frac{ - 68}{14} = \frac{ - 34}{7}$.

▶ Put the value of ‘x’ in equation (1), we get

=> y = $\frac{1 - 2x}{3}$

=> y = $\frac{1 - 2 ( \frac{ - 34}{7}}{3}$

$= > y = \frac{1 + \frac{68}{7} }{3} .$

$= > y = \frac{ \frac{7 + 68}{7} }{3} .$

$= > y = \frac{ \frac{75}{7} }{3} .$

$= > y = \frac{25}{7} .$

✔✔ Hence, x = $\frac{ - 34}{7}$. and y = $\frac{25}{7}$. ✅✅

OR.

▶Solve by elimination method :-)

3x + 4y = 10.

2x - 2y = 2.

▶ Solution :-)

Given equation :-

3x + 4y = 10..........(1).

2x - 2y = 2............(2).

▶ Now, multiply equation (1) by 2 and equation (2) by 3, we get

=> 2( 3x + 4y = 10 ).

=> 6x + 8y = 20.........(3).

And,

=> 3( 2x - 2y = 2 ).

=> 6x - 6y = 6...........(4).

▶Now, Substracte in equation (3) and (4), we get

6x + 8y = 20.
6x - 6y = 6.
(-)....(+)......(-)
__________

=> 14y = 14.

=> y = 14/14.

=> y = 1.

▶ Putting the value of ‘y’ in equation (2), we get

=> 2x - 2 × 1 = 2.

=> 2x - 2 = 2.

=> 2x = 2 + 2.

=> 2x = 4.

=> x = 4/2.

=> x = 2.

✔✔ Hence, x = 2 and y = 1. ✅✅

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$\huge \boxed{ \mathbb{THANKS}}$

$\huge \bf{ \#BeBrainly.}$

Answer 2

Hey ...here is yr answer -------

Given;
The pair of equation;


$3x + 4y = 10 .......(1)$
$2x - 2y = 2......(2)$
$(1) \times 2 = 6x + 8y = 20$
$(2) \times 3 = 6x - 6y = 6$
(+) (-)


$14y = 14$
$y = 1$
Now;
putting the value of y in equation (1) we get;

$3x + 4y = 10$
$3x + 4(1) = 10$
$3x = 10 - 4$
$3x = 6$
$x = 2$


Therefore;
X=2
y=1



Hope; this answer is correct.
$thanks$