Math, asked by Ramlayaksingh3, 11 months ago

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Answered by siddhartharao77
1

Answer:

2/3

Step-by-step explanation:

Given Equation is 5x² + 2x - 3.

On comparing with ax² + bx + c = 0,

a = 5, b = 2, c = -3.

(i)

We know that Sum of roots = -b/a

α + β = -2/5.


(ii)

We know that Product of roots = c/a

αβ = -3/5.


Now,

⇒ (α/β) + (β/α)

⇒ (α² + β²)/αβ

We know that (α + β)² = α² + β² + 2αβ

⇒ (-2/5)² = α² + β² + 2(-3/5)

⇒ 4/25 = α² + β² - 6/5

⇒ 34/25 = α² + β².

Now,

⇒ (34/25)/-3/5

⇒ -34/15


Hope it helps!


Ramlayaksingh3: sir you missed one thing
Ramlayaksingh3: a/b+b/a=(a+b)^2/ab !!
siddhartharao77: How come it will be (a + b)^2?
Ramlayaksingh3: i mean a^2 +b^2 .
siddhartharao77: then it will be -34/15 instead of 34/15
Ramlayaksingh3: yes I am also getting the same answer
Ramlayaksingh3: thank you sir
siddhartharao77: welcome
Answered by Siddharta7
0

Answer:

-34/15

Step-by-step explanation:

Given Equation is 5x² + 2x - 3.

On comparing with ax² + bx + c = 0,

a = 5, b = 2, c = -3.

(i)

We know that Sum of roots = -b/a

α + β = -2/5.

(ii)

Product of roots = c/a

αβ = -3/5.

Now,

(α/β) + (β/α)

(α² + β²)/αβ

(-2/5)² = α² + β² + 2(-3/5)

4/25 = α² + β² - 6/5

34/25 = α² + β².

(34/25)/-3/5

-34/15


Siddharta7: brainliest any answer
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