Question

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Please do fast........∆¶​

Answer 1

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REFER TO THE ATTACHMENT FOR YOUR SOLUTIONS.

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Answer 2

1 sin theta = cos theta

[Since, cos theta = sin(90° - theta)]

= sin theta = sin (90° - theta)

= theta = 90° - theta

= theta + theta = 90°

= 2 theta = 90°

= theta = 90°/2

= theta = 45°

2 tan theta = cot (30° + theta)

[Since, tan theta = cot (90° - theta)]

= cot (90°- theta) = cot (30° + theta)

= 90° - theta = 30° + theta

= 90° - 30° = theta + theta

= 60° = 2 theta

= theta = 60°/2

= theta = 30°

3 sin theta = cos (theta - 6°)

[Since, sin theta = cos (90° - theta)]

= cos (90°- theta) = cos (theta - 6°)

= 90°- theta = theta - 6°

= 90° + 6° = theta + theta

= 96° = 2 theta

= theta = 96°/2

= theta = 48°